Ohm's Law confusion ...
Ohm's Law confusion ...
Hi, something confusing me here.
I have a 12-volt, incandescent light bulb, the resistance of which is 17.5 Ohms.
According to Ohm's Law, if i allow the bulb 12 volts, the current flowing through it should be :
I = V/R = 12/17.5 = 0.7 Amps.
This sounded a lot to me for a tiny light bulb, so i powered it with my DC PSU (which has LCD readouts for Voltage/Current) and it only drew 75mA.
What is it that i don't know, does resistance go up when a load is powered ?
Any help greatly appreciated,
DC.
I have a 12-volt, incandescent light bulb, the resistance of which is 17.5 Ohms.
According to Ohm's Law, if i allow the bulb 12 volts, the current flowing through it should be :
I = V/R = 12/17.5 = 0.7 Amps.
This sounded a lot to me for a tiny light bulb, so i powered it with my DC PSU (which has LCD readouts for Voltage/Current) and it only drew 75mA.
What is it that i don't know, does resistance go up when a load is powered ?
Any help greatly appreciated,
DC.
Re: Ohm's Law confusion ...
I think i've figured it, is it because of the rise in temperature in the filament ?
Cheers,
DC.
Cheers,
DC.
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Re: Ohm's Law confusion ...
Indeed, the resistance of the filament is a lot lower when cold than when heated up, hence why light bulbs tend to blow at switch-on.